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You need to draw FBD's of the crank and of the block individually. From the crank you will have a moment equation (note that since the crank is negligible, its mass moment of inertia is zero). From the block you will use Newton's second law.
Combine together these two equations along with kinematics relating the motion of A to the motion of B.
If our EOM includes something to the right of the = sign, for instance, say my EOM is x_dot_dot + c/m*x_dot + k/m = m*g, is that alright for a final answer? Also, in the equation c/m = 2*squiggle*w_n, is the c/m an equivalent term based on your EOM, much like w_n is calculated using an equivalent term?
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You need to draw FBD's of the crank and of the block individually. From the crank you will have a moment equation (note that since the crank is negligible, its mass moment of inertia is zero). From the block you will use Newton's second law.
Combine together these two equations along with kinematics relating the motion of A to the motion of B.
from the crank, I got:
-F_A * a - F_B * b = 0
and from the block, I got:
F_A - k * x = m * x_dot_dot
How do I use the kinematics to relate them?
Let yB be the displacement of point B to the right. With that, FB = c*yB_dot (within a sign -- not sure of how your drew FB on your FBD).
You need kinematics to relate yB_dot to x_dot.
If our EOM includes something to the right of the = sign, for instance, say my EOM is x_dot_dot + c/m*x_dot + k/m = m*g, is that alright for a final answer?
Also, in the equation c/m = 2*squiggle*w_n, is the c/m an equivalent term based on your EOM, much like w_n is calculated using an equivalent term?
In above comment, when I said squiggle, I meant zeta.
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