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Sunday, December 2, 2007

8/48

Are we not supposed to do part a since we didn't go over these problems with a c>0?
I am also having trouble getting the solution set up for this problem. Where does the weight come into play. and so omega_n is not = to 120.

2 comments:

Pat Alonzi said...

The weight can be assumed negligible since it is a "Static Force" the Equation of Motion is concerned with the Dynamic forces. For more info consider the example prob 8.6

CMK said...

--to lemerson--
Problems 8/48 and 8/54 each have a part for which you are asked to find the response for c = 0 (undamped). Since we did not get to damped, forced response in class on Friday, I will instruct the grader to grade only the undamped part of the problem.

For 8/48, 10 kg represents the mass of the particle. Your EOM for this problem will show that omega_n = sqrt(k/m) where k = 100,000 N/m and m = 10 kg. Note that the excitation is harmonic with a frequency of omega = 120 rad/sec. Both omega and omega_n appear in the forced response. You are correct -- omega_n is not equal to 120 rad/sec (non-resonance).

Let me know if I missed the point of your question.