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Why exactly is I_G zero for part A? Is it because the rod has a radius negligible to that of the the hoop? (I think that's what you were getting at in the video) But wouldn't the rod's length play some role in I, making I_G nonzero?
Yes, it has to do with the radius of the rod being small compared to the radius of the outer surface of the wheel.
In general, you would write I_G for the rod as: I_G = 0.5*m*R^2 where R is the radius of the rod. So here we are saying that r >> R. The length of the rod is only an indirect factor for rotation about its centerline. (The length of the rod influences only the mass m.)
2 comments:
Why exactly is I_G zero for part A? Is it because the rod has a radius negligible to that of the the hoop? (I think that's what you were getting at in the video) But wouldn't the rod's length play some role in I, making I_G nonzero?
Yes, it has to do with the radius of the rod being small compared to the radius of the outer surface of the wheel.
In general, you would write I_G for the rod as: I_G = 0.5*m*R^2 where R is the radius of the rod. So here we are saying that r >> R. The length of the rod is only an indirect factor for rotation about its centerline. (The length of the rod influences only the mass m.)
I hope this helps. If not, let us know.
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