I have a question on this problem. using the impulse equation in the x and the y for the single partical. I get MVx1 = MVx2 therefore Vx2 = Vx1
Also, in the Y I get that the integral of 2t * (3t^2)/4 = MVy2-MVy1
After evaluating the integral and solving for V2 I am getting a number of 11.0805 instead of 8.06. Any ideas?
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2 comments:
Well make sure your integral is correct first. It looks like you have a 2t when it should only be a t (before you take the integral) and make sure your sign is correct on your MVy1. It looks like you have it in the positive Y-dir. when it should be in the negative... See if that helps.
my mistake was actually much simpler. I was multiplying instead of adding after I integrated. Sometimes it helps to walk away for awhile.
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