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i having trouble getting the answer in the book. Ho=(6i+8j) x (2*(7cos(30)i + 7sin(30)j), but I am coming up a little short of the answer they get in the book. I dont know if I am missing something important or not
Make sure you get right sign for negative x-y direction. Check trigonometry also in ur equation. Equation shoould be Ho=(-6i+8j) x (2*(-7sin(30)i -7cos(30)j)
I was confused about the second part as well but I think it would just be finding what r is by doing the square root of square of both of the sides and doing the same for the velocity and pluging that into the original equation.
5 comments:
Make sure you get right sign for negative x-y direction. Check trigonometry also in ur equation.
Equation shoould be Ho=(-6i+8j) x (2*(-7sin(30)i -7cos(30)j)
Based on your original Ho equation its definitely a matter of signs in both your velocity as well your radius.
What does it mean to solve it using an equivalent scalar approach? What equation would be used for that?
I was confused about the second part as well but I think it would just be finding what r is by doing the square root of square of both of the sides and doing the same for the velocity and pluging that into the original equation.
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