Here you can add discussion posts as well as add comments to existing posts. Links are also provided to solution videos and other pages of the course website for your easy access.
The solution of Exam No. 1 has been posted on the Exam page of the course website (see link to the page in the box at the right side of this blog page).
Let me know if you have any questions on the exam and/or its solution. Feel free to share your thoughts on the exam.
It looks like the server for the ME274 website is down. This is usually a temporary thing. Check back in a couple hours and hopefully it will be back up. I will contact the Eshop people to see if someone is working on getting it fixed.
Not necessarily. For example, if a link is oscillating back at forth, at the extremes of its oscillation it has to come to a complete stop (aka omega = 0) but it could still have an angular acceleration. To give you a mathematical example, say omega = t^2 + 2t. The first time derivative would be 2t + 2. Here omega(0) = 0, but omega' = alpha = 2.
Will we be graded more on the correct answers or the the method we used to get them, because i think in every problem i used the right method but probably made some number erorr and got different answers.
10 comments:
I am unable to open the Exams link. Error 404 page not found. Is anyone having the same problem?
It looks like the server for the ME274 website is down. This is usually a temporary thing. Check back in a couple hours and hopefully it will be back up. I will contact the Eshop people to see if someone is working on getting it fixed.
I didn't think the exam was that bad. I just hope I didn't make too many 'rushed' errors.
I have a question here. Will angular acceleration be 0 if angular velocity is 0 since alpha = d/dt(omega)
Not necessarily. For example, if a link is oscillating back at forth, at the extremes of its oscillation it has to come to a complete stop (aka omega = 0) but it could still have an angular acceleration. To give you a mathematical example, say
omega = t^2 + 2t. The first time derivative would be 2t + 2. Here omega(0) = 0, but omega' = alpha = 2.
Will we be graded more on the correct answers or the the method we used to get them, because i think in every problem i used the right method but probably made some number erorr and got different answers.
Grading is based on correct procedure and execution of that procedure. Numerical errors are not heavily penalized.
oh, okey... thanks!
--to andrew crandell--
Excellent comment to elaine's question! You used both physical and mathematical examples to explain.
I hope that your comment helps everyone in understanding this very important concept.
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