Suggestions
First use the method of instant centers to determine the angular velocity of link AB. To do so, determine the directions of the velocities of points A and B on link AB. Construct perpendiculars to these two velocities. Where these two perpendicular intersect is the location of the IC for link AB. Using this information, you can find the angular speed and direction of rotation for link AB.
Now, use the location of the IC for AB to find the speed of point G on AB. Here the speed of G is the angular velocity of AB times the distance for the IC of AB to point G.
3 comments:
I found the velocity of G to be .48 m/s or .42i + .24j m/s if its sposed to be in vector form. did anyone get these answers? does anyone know what form its sposed to be in?
I got the velocity to be in the same direction as you (30 degrees up and to the right from the horizontal, but my velocity is almost 1/2)
-- to jonbrueck--
I do not have the textbook with me so I do not know how the question is written. If it says speed, then you only need to give the magnitude of the velocity. It it asks for velocity, then write answer as vector, as you have.
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