* First locate the IC for each wheel (recall that these wheels do not slip).
* The velocity of the IC's for the wheels have zero velocity.
* The acceleration of the IC's for the wheels do NOT have zero acceleration. No slip implies only that the horizontal component of acceleration of the contact point is zero; the vertical components of the acceleration of the no-slip points are not zero.
* Use the rigid body kinematics equations to find the angular velocity and angular acceleration of the wheel on the right. Also find the acceleration of point A.
* Recognize that the horizontal component of acceleration of A is the same as the horizontal component of acceleration of B.
* Use the rigid body kinematics equations to find the angular velocity and angular acceleration of the wheel on the left.
* Now you can find the acceleration of D using the rigid body acceleration equation.
As you can see, this problem requires the usage of the velocity and acceleration rigid body equations for EACH rigid body. This is true for ALL problems that we will see this semester.
3 comments:
I've noticed that in the question they haven't given us the value of x or the distance between the two wheels. So I would assume that our final answer will be an algebraic solution?
Yes, leave x as an unknown throughout the problem. I suspect that you will find that the final answer is independent of x. (I do not see how the distance between the two wheels would affect the answer.)
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